RATE ANALYSIS OF CEMENT MORTAR

Step 1:- Assumptions

Volume of mortar= 1 m³

Mix Ratio –> 1:6

Step 2:- Volume of Plaster

Dry volume of mortar = Wet volume x 1.33

∴ Dry Volume = 1.0 m³x 1.33 = 1.33 m³

Step 3:- Quantity of Cement

Quantity of Cement = {(Dry Volume of mortar x Cement ratio) / (Sum of the ratio)}

∴Quantity of cement = (1.33 x 1) /(1+6)=0.19 m³

Density of Cement = 1440 kg/m³

∴ Weight of Cement = 1440 x 0.19 = 273.6 Kg

1 bag of cement contains 50 kg of cement

∴ Number of bags = 273.6 Kg/50 = 5.472 No’s

Step 4:- Quantity of Sand

Cement : Sand :: 1:6

Quantity of Sand = Quantity of Cement x 6

∴ Quantity of Sand = 0.19 m³ x6= 1.14 m³

1m³=35.3147 Cubic Feet (CFT)

∴ Quantity of sand = 1.14 x 35.3147 = 40.258 CFT

Density of sand = 1920 kg/m³

∴ Weight of the sand= 1.14m³x1920kg/m³= 2380.8 kg =>2.3808 tonnes

Step 5:- Cost calculation

i) Material Cost:

Material for one cu. m. Quantity rate per Amount
Cement 5.472 bags Rs. 350 bag Rs. 1915.2
Sand 1.14 m³ Rs. 1350 Rs. 1539
Total Rs. 3454.2

ii) Labour Cost:

Labours for 1m³ No’s Wages/day Amount
Mazdoor 0.75 Rs. 500 Rs. 375
Bhisti 0.07 Rs. 400 Rs. 28
Rs. 403

Screenshot (535)

Summary:

Cost of material = Rs. 3454.2

Cost of labours = Rs. 403

Sum of labour & material cost= Rs. 3857.2

Add:

1.Water charge @ 1.5% = (1.5/100)x3857.2 = Rs. 57.858

2.Contractor’s profit @10 % = (10/100)x3857.2= Rs. 385.72

Total cost = 3857.2 + 57.858 +385.72= Rs. 4300.778

Watch the video in the below link for better understanding and detailed explanation.

RATE ANALYSISI OF CEMENT MORTAR

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