Quantity of cement = (Dry volume of concrete x cement ratio)/(sum of the ratio’s of cement, sand & aggregates)
Assume, Volume of concrete = 1 m³
Wet volume of concrete = 1 m³
Dry volume = Wet volume x 1.54
Dry volume of concrete = 1 x 1.54 =1.54 m³
M25
Grade of concrete M25 — 1:1:2 (Cement: Sand: Aggregates)
Quantity of cement =( 1.54 x 1)/(1+1+2) = 0.385 m³
Density of cement = 1440 kg/m³
One bag of cement = 50 kg
No. of bags in 1 m³ = 1440/50 = 28.8 no’s
No. of bags = 0.385 x 28.8 = 11.088 no’s
M20
Grade of concrete M20 — 1:1.5:3 (Cement: Sand: Aggregates)
Quantity of cement =( 1.54 x 1)/(1+1.5+3) = 0.28 m³
No. of bags = 0.28 x 28.8 = 8.064 no’s
M15
Grade of concrete M15 — 1:2:4 (Cement: Sand: Aggregates)
Quantity of cement =( 1.54 x 1)/(1+2+4) = 0.257 m³
No. of bags = 0.257 x 28.8 = 7.392 no’s
M10
Grade of concrete M10 — 1:3:6 (Cement: Sand: Aggregates)
Quantity of cement =( 1.54 x 1)/(1+3+6) = 0.154 m³
No. of bags = 0.154 x 28.8 = 4.435 no’s
M7.5
Grade of concrete M7.5 — 1:4:8 (Cement: Sand: Aggregates)
Quantity of cement =( 1.54 x 1)/(1+4+8) = 0.119 m³
No. of bags = 0.119 x 28.8 = 3.412 no’s
M5
Grade of concrete M5 — 1:5:10 (Cement: Sand: Aggregates)
Quantity of cement =( 1.54 x 1)/(1+5+10) = 0.0963 m³
No. of bags = 0.0963 x 28.8 = 2.2772 no’s
SUMMERY
Grade of concrete | No. of bags of cement per m³ |
M25 | 11.088 |
M20 | 8.064 |
M15 | 7.392 |
M10 | 4.435 |
M7.5 | 3.412 |
M5 | 2.772 |
Watch the video in the below link for better understanding and detailed explanation.