# How to Calculate Quantity of Bricks, Cement, Sand for Brickwork in a Building?

Q:- For a given plan find
(i) No. of bricks
(ii) C:M required for Brick work with ratio 1:6
D = 1.0 X 2.10
Height of Ceiling = 3.0 m

Solution:

• ##### For External wall or 20 cm wall

Length of wall (L ) = 10.40 x 2 + 4.0 x 2 = 28.80 m
L = 28.80 m
B = 0.20 m
D = 3.0 m

Volume of brickwork = Length x width x Thickness of wall

= 28.80 x 3.0 x 0.20

= 17.28 m³

• For internal wall or 10 cm wall

Length of wall (L ) = 4.0 m
L = 4 m
B = 0.20 m
D = 3.0 m

Volume of brickwork = Length x width x Thickness of wall

= 4.0 x 3.0 x 0.10

= 1.2 m³

∴ Total volume brickwork =  1.2 + 17.28 = 18.48

Deduction of Door = L x B x D = 1.0 x 2.10 x 0.20 = ‐0.42 m³

Deduction of Internal Door = L x B x D = 1.0 x 2.10 x 0.10 = -0.21 m³

Deduction of Door Lintel = L x B x D = 1.20 x 0.10 x 0.20 = ‐0.024 m³

Since, Breadth of Lintel = thickness of wall = 0.20 m

Deduction of Internal Door Lintel = L x B x D = 1.20 x 0.10 x 0.10 = 0.012 m³
Since, Breadth of Lintel = thickness of wall = 0.10 m

Total Volume of brick work after deductions = 18.48 ‐ 0.42 ‐ 0.024 – 0.21 -0.012= 17.814 m³

Assuming:-

1. Brick size = 19cm x 19cm x 19cm
2. Thickness of mortar = 10 mm

### Quantity of Bricks:-

No. of bricks         =         Volume of brickwork
volume of 1 brick with mortar

= 17.814/0.002

∴ No. of bricks = 8907 bricks

Volume of 1 Brick with mortar = 0.20×0.10×0.10=0.002 m³

### CM required for brickwork:-

Volume of total no.of bricks = (0.19×0.09×0.09) x 8907

= 0.001539 x  8907

= 13.7079 m³

Quantity of mortar = Quantity of brickwork – Volume of bricks

Quantity of mortar = 17.814 –  13.7079

= 4.1061 m³

Mix Ratio –> 1:6

Dry volume of mortar = Wet volume x 1.33

∴Dry volume of mortar = 4.1061 m³x 1.33

= 5.4611 m³

### Quantity of cement:-

Quantity of Cement = Dry Volume of mortar x Cement ratio
Sum of the ratio

∴Quantity of cement = (5.4611 x 1) /(1+6)

=  0.7802 m³

Density of Cement = 1440 kg/m³

∴ Weight of Cement = 1440 x  0.7802

= 1123.488 Kg

1 bag of cement contains 50 kg of cement

∴ Number of bags = 1123.488 Kg / 50 kg

= 22.4697 No’s

### Quantity of Sand:-

Cement : Sand :: 1:6

Quantity of Sand = Quantity of Cement x 6

∴ Quantity of Sand = 0.7802 m³x 6

= 4.6812

1 m³=35.3147 Cubic Feet (CFT)

∴ Quantity of sand = 4.6812 x 35.3147

= 165.315 CFT

Density of sand = 1650 kg/m³

∴ Weight of the sand = 4.6812 x 1650

= 7723.98 kg

=7.7239 tonnes

Watch the video given in the link below, for better understanding and detailed explanation

Easy method to CALCULATE NO OF BRICKS AND QUANTITY OF CEMENT & SAND in BRICKWORK

Click here to download pdf of “How to Calculate Quantity of Bricks, Cement, Sand for Brickwork in a Building”

Password to open the file:- wecivilengineers.blog Advertisements
Categories: