Q:- For a given plan find (i) No. of bricks (ii) C:M required for Brick work with ratio 1:5.

D = 1.0 X 2.10

Height of Ceiling = 3.0 m

Solution:

Length of wall (L ) = 5.40 x 2 + 4.0 x 2 = 18.80 m

L = 18.80 m

B = 0.20 m

D = 3.0 m

**Volume of brickwork = Length x width x Thickness of wall**

= 18.80 x 3.0 x 0.20

= 11.28 m³

Deduction of Door = L x B x D = 1.0 x 2.10 x 0.20 = ‐0.42 m 3

Deduction of Door Lintel = L x B x D = 1.20 x 0.10 x 0.20 = ‐0.024 m 3

Since, Breadth of Lintel = thickness of wall = 0.20 m

Total Volume of brick work after deductions = 11.28 ‐ 0.42 ‐ 0.024 = 10.836 m3

**Assuming:-**

- Brick size = 19cm x 9cm x 9cm
- Thickness of mortar = 10 mm

### Quantity of Bricks:-

**No. of bricks = Volume of brickwork
**

**volume of 1 brick with mortar**

= 10.836/0.002

∴ No. of bricks = 5418 bricks

Volume of 1 Brick with mortar = 0.20×0.10×0.10=0.002 m³

**CM required for brickwork:-**

Volume of total no.of bricks = (0.19×0.09×0.09) x 5418

= 0.001539 x 5418

= 8.3383 m³

**Quantity of mortar = Quantity of brickwork – Volume of bricks**

Quantity of mortar = 10.836 – 8.3383

= 2.4977 m³ ≅ 2.5 m³

**Mix Ratio –> 1:6**

**Dry volume of mortar = Wet volume x 1.33**

∴Dry volume of mortar = 2.5 m³x 1.33

= 3.325 m³

**Quantity of cement:-**

**Quantity of Cement = Dry Volume of mortar x Cement ratio
**

**Sum of the ratio**

∴Quantity of cement = (3.325 x 1) /(1+6)

= 0.475 m³

**Density of Cement = 1440 kg/m****³**

∴ Weight of Cement = 1440 x 0.475

= 684 Kg

**1 bag of cement contains 50 kg of cement**

∴ Number of bags = 684 Kg / 50 kg

= **13.68**** No’s**

**Quantity of Sand:-**

**Cement : Sand :: 1:6**

**Quantity of Sand = Quantity of Cement x 6**

∴ Quantity of Sand = 0.475 m³x 6

= **2.85 ****m³**

**1 m³=35.3147 Cubic Feet (CFT)**

∴ Quantity of sand = 2.85 x 35.3147

= 100.647 CFT

**Density ****of sand = 1650 kg/m³**

∴ Weight of the sand = 2.85 x 1650

= 4702.5 kg

=4.7025 tonnes

**Watch the video given in the link below, for better understanding and detailed explanation**

Easy method to CALCULATE NO OF BRICKS AND QUANTITY OF CEMENT & SAND in BRICKWORK

Click here to download pdf of “How to calculate number of bricks, Cement & Sand required for a room?”

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