How to calculate number of bricks, Cement & Sand required for a room?

Q:- For a given plan find (i) No. of bricks (ii) C:M required for Brick work with ratio 1:5.

D = 1.0 X 2.10
Height of Ceiling = 3.0 m

Solution:

Length of wall (L ) = 5.40 x 2 + 4.0 x 2 = 18.80 m 
L = 18.80 m 
B = 0.20 m
D = 3.0 m

Volume of brickwork = Length x width x Thickness of wall

= 18.80 x 3.0 x 0.20

= 11.28 m³

Deduction of Door = L x B x D = 1.0 x 2.10 x 0.20 = ‐0.42 m 3
Deduction of Door Lintel = L x B x D = 1.20 x 0.10 x 0.20 = ‐0.024 m 3
Since, Breadth of Lintel = thickness of wall = 0.20 m

Total Volume of brick work after deductions = 11.28 ‐ 0.42 ‐ 0.024 = 10.836 m3

Assuming:-

1. Brick size = 19cm x 9cm x 9cm
2. Thickness of mortar = 10 mm

Quantity of Bricks:-

No. of bricks         =         Volume of brickwork           
                                         volume of 1 brick with mortar

        = 10.836/0.002

     ∴ No. of bricks = 5418 bricks 

Volume of 1 Brick with mortar = 0.20×0.10×0.10=0.002 m³

CM required for brickwork:-

Volume of total no.of bricks = (0.19×0.09×0.09) x 5418 

                                                      = 0.001539 x  5418

                                                      = 8.3383 m³

Quantity of mortar = Quantity of brickwork – Volume of bricks

Quantity of mortar = 10.836 –  8.3383

                                       = 2.4977 m³ ≅ 2.5 m³ 

Mix Ratio –> 1:6

Dry volume of mortar = Wet volume x 1.33

 ∴Dry volume of mortar = 2.5 m³x 1.33

                                               = 3.325 m³

Quantity of cement:-

Quantity of Cement = Dry Volume of mortar x Cement ratio
                                                         Sum of the ratio

∴Quantity of cement = (3.325 x 1) /(1+6)

                                         =  0.475 m³

Density of Cement = 1440 kg/m³

∴ Weight of Cement = 1440 x  0.475

                                        = 684 Kg

1 bag of cement contains 50 kg of cement

∴ Number of bags = 684 Kg / 50 kg

                                    = 13.68 No’s

Quantity of Sand:-

Cement : Sand :: 1:6

Quantity of Sand = Quantity of Cement x 6

∴ Quantity of Sand = 0.475 m³x 6

                                      = 2.85 m³

1 m³=35.3147 Cubic Feet (CFT)

∴ Quantity of sand = 2.85 x 35.3147

                                     = 100.647 CFT

Density of sand = 1650 kg/m³

∴ Weight of the sand = 2.85 x 1650

  = 4702.5 kg

  =4.7025 tonnes 

Watch the video given in the link below, for better understanding and detailed explanation

Easy method to CALCULATE NO OF BRICKS AND QUANTITY OF CEMENT & SAND in BRICKWORK

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