How to calculate brick, sand and cement in brick masonry?

For an area of 2000 ft² with wall thickness 20 cm find
(i) No. of bricks
(ii) C:M required for Brick work with ratio 1:5

Solution:

Assuming:-

  1. Brick size = 19cm x 19cm x 19cm
  2. Thickness of mortar = 10 mm

Before we get into the calculation part, Let’s convert ft² to m² for convenient of calculations. 

2000 ft² = ? m²
            = 2000/3.28²                              (since 1 m = 3.28 ft)
            = 185.901 m²

Volume of brickwork = Area x Thickness of wall

                                             = 185.901 x 0.20

                                             = 37.1802 m³

Quantity of Bricks:-

No. of bricks         =         Volume of brickwork           
                                         volume of 1 brick with mortar

        = 37.1802/0.002

     ∴ No. of bricks = 18590 bricks 

Volume of 1 Brick with mortar = 0.20×0.10×0.10=0.002 m³

CM required for brickwork:-

Volume of total no.of bricks = (0.19×0.09×0.09) x 18590  

                                                      = 0.001539 x 18590

                                                      = 28.61 m³

Quantity of mortar = Quantity of brickwork – Volume of bricks

Quantity of mortar = 37.1802 – 28.61

                                       = 8.5702 m³

Mix Ratio –> 1:5

Dry volume of mortar = Wet volume x 1.33

 ∴Dry volume of mortar = 8.5702 m³x 1.33

                                               = 11.3984 m³

Quantity of cement:-

Quantity of Cement = Dry Volume of mortar x Cement ratio
                                                         Sum of the ratio

∴Quantity of cement = (11.3984 x 1) /(1+5)

                                         =  1.8997 m³

Density of Cement = 1440 kg/m³

∴ Weight of Cement = 1440 x 1.8997

                                        = 2735.616 Kg

1 bag of cement contains 50 kg of cement

∴ Number of bags = 2735.616 Kg / 50 kg

                                    = 57.712 No’s

Quantity of Sand:-

Cement : Sand :: 1:5

Quantity of Sand = Quantity of Cement x 5

∴ Quantity of Sand = 1.8997 m³x 5

                                      = 9.4985 

1 m³=35.3147 Cubic Feet (CFT)

∴ Quantity of sand = 9.4985 x 35.3147

                                     = 335.436 CFT

Density of sand = 1650 kg/m³

∴ Weight of the sand = 9.4985  x 1650

  = 15672.53 kg

  =15.6725 tonnes 

Watch the video given in the link below, for better understanding and detailed explanation

Easy method to CALCULATE NO OF BRICKS AND QUANTITY OF CEMENT & SAND in BRICKWORK

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